Current and Electric Circuits :: Problem 13

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Problem 13: The battery of pocket calculator supplies 0.35A at a potential difference of 6V. What is the power rating of calculator?

Solution:

Step: 1 Overview

See the overview of problem 3.

Given:

V=6V
I=0.35A

Required:

P=?

Solution:

We know that,
P=VI
P=(6)(0.35)
P=2.1W (Ans)