Solution:
Step: 1 Overview
See the overview of problem 2.Step: 2 Calculation
Given:r=0.4mSolutions:
T1=0oC
T2=100oC
ΔT=100-0=100oC
β (for aluminium)= 7.2x10-5
We know that:
Volume of sphere = 4.19r3
V = 4.19(0.4)3
V = 4.19(0.064)
V = 0.26816
Also we know that:
ΔV = βVΔT
ΔV = (7.2x10-5)(0.26816)(100)
ΔV = 0.00193m3 (Ans)